cannot be used as a function

问题描述:C语言自定义函数显示can't be use as a function 本篇文章给大家谈谈cannot be used as a function翻译,以及一个有趣的事情,希望对各位有所帮助,不要忘了收藏本站喔。

简单C语言编程,‘jdjd’ cannot be used as a function

cannot be used as a function的相关图片

dist变量名和dist函数同名了 还有函数调用的参数顺序错了

f <em>cannot</em> e <em>used</em> <em>as</em> a <em>function</em>什么意思啊?的相关图片

f cannot e used as a function什么意思啊?

include<stdio.h>double jdjd(int x);double jdjd(int x) // 原来的有警告,修改如下{if( x>=90 && x<=100)return 4.0;else if(x>=85)return 3.7;else if(x>=82)return 3.3;else if(x>=78)ret

expression <em>cannot</em> <em>be</em> <em>used</em> <em>as</em> a <em>function</em> 翻译中文的相关图片

expression cannot be used as a function 翻译中文

F不能用于作为一个功能

'p' can ont <em>be</em> <em>used</em> <em>as</em> a <em>function</em>. else前面还少了一个‘;’ 那位可...的相关图片

'p' can ont be used as a function. else前面还少了一个‘;’ 那位可...

k=s((s[i]+s[j])%n); 编译器将第一个s认为是函数名了 改为k=s[(s[i]+s[j])%n];

c++ error: 'Perimeter' cannot be used as a function

if( (a+b<=c) || (b+c <= a) || (c+a <=b)){ printf("Can not form a triangle.\n");}else{ p=(a+b+c)/2;S=sqrt(p*(p-a)*(p-b)*(p-c));printf("%.3f\n",S);} return 0;} ...

原文地址:http://www.qianchusai.com/cannot%20be%20used%20as%20a%20function.html

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